Question

If y=3x+7, prove that y3 -27x3 -343-63xy =0.

Answer 1

y=3e2x+2e3x

⇒dydx=3e2x(2)+2e3x(3)

⇒dydx=6(e2x+e3x)

⇒d2ydx2=6(2e2x+3e3x)

Now,L.H.S.=d2ydx2−5dydx+6y

=12e2x+18e3x−30e2x−30e3x+18e2x+12e3x

Answer 2

Answer:

Given equation is y=3x

When x=1,⇒y=3×1=3

When x=2,⇒y=3×2=6

When x=3,⇒y=3×3=9

x 1 2 3

y 3 6 9

Plot the points A(1,3),B(2,6),C(3,9) on the graph paper.Join these points by a straight line AC