If y = 5sin (3t omega + alpha), find dy/dt if el omega and alpha are constant
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Let omega = w
and, alpha = a
Thus,
y = 5sin(3t omega + alpha)
y = 5sin(3tw + a)
Differentiate y with respect to t,
dy/dt = 5[sin(3tw+a)]'
= 5[cos(3tw+a)]×(3tw+a)'
= 5[cos(3tw+a)]×3w
= 15w.Cos(3tw+a)
= 15omega×Cos(3t omega + alpha)
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