If y=a(1-cos theta) and x =a(theta +sin theta),then find the value of dy/dx at theta =pi/2
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y = a (1 – cos θ)
x = a ( θ + sinθ)
dy/dθ = a (0 -(-sinθ)) = a sin θ
dx/dθ = a (1+cos θ)
dy/dθ divided by dx/dθ = sin θ/ 1+cosθ
At θ = π/2
dy/dx = 1/1+0
dy/dx = 1
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