Question

In an isosceles triangle ABC with AB =AC , BD and CE are two medians . prove that BD = CE

Answer 1

I solved it on a sheet of paper with clear explanations written beside it. Any doubts then please do ask without any hesitation. Hope this was helpful

Answer 2

Answer:

T.P.T. (i) ∆ AEX ~ ADB

(ii) CA / AB = CE / DB

P.F. (i) In ∆ AEC and ∆ ADB

∠1 = ∠2 (each 90°)

∠A = ∠A (common)

∴ ∆ AEC ~ ∆ ADB (by AA rule)

(ii) ∆ AEC ~ ∆ ADB

CA / AB = CE / DB (∵ angles are similar)

∴ Corresponding sides are proportional) H.P.

Step-by-step explanation:

@Genius