If y = (A÷B) sin (Bt) where A and B are constants t is time and y is distance then dimensional formula of AB is given by
The answer is L^1 T^(-2).
I want explanation
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Explanation:
[A/B] = [y] = [L]
=> [A] =[B][L]
=> [AB] = [B]^2 [L] ...... (1)
now,
[Bt] = [1] .........(angle is dimensionless quality)
=> [B] = [1/t] = [T^-1] .... (2)
using (1) & (2) ..
[AB] = [L T^-2]
* * * * * *
hope, it helps you.
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