Question

Prove that sin^6 θ + cos^6 θ + 3 sin^2 θ cos^2 θ = 1​

Answer 1

Answer:

LHS = (sin^2 θ)^3 + (cos^2 θ)^3 + 3 sin^2 θ cos^2 θ

= (sin^2 θ + cos^2 θ)^3

= 1^3 = 1 = RHS

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Step-by-step explanation: