If y=Asinx+Bcosx,then what is y(0)
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Answer:
Step-by-step explanation:
Differentiate y=Asinx+Bcosx with respect to x.
dx
dy
=Acosx−Bsinx
Again differentiate with respect to x.
dx
2
d
2
y
=−Asinx−Bcosx
dx
2
d
2
y
=−(Asinx+Bcosx)
dx
2
d
2
y
=−y
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