Question

if 10x square +ax-17=(5x+1) (2x-17) then find a
pls help me ​

Answer 1

An equation remains the same if the LHS and the RHS are ... (d) 5. Solution : Correct answer is (c). Example 2: –1 is not a solution of the ... To solve an equation that contains a variable, find the value of the variable ... ax = b will always be a ... 7. (c) 2. (d) 3. 7. The solution of the equation 3x + 7 = – 20 is. (a). 17. 7. (b) – 9.

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Answer 2

Answer:

10x^2+ax-17=(5x+1)(2x-17)

=> 10x^2+ax-17=10x^2+2x-85x-17

=> 10x^2+ax-17=10x^2-83x-17

=> 10x^2+ax-10x^2= -83x-17+17

=> ax= -83x

=> a= -83

so, a= -83