Question

If y = ax + bx^2 then the corresponding
difference equation is
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Answer 1

Answer:

Given equation is  $y = ax + bx^2$

We need to find the differentiated equation.

∴    $y' = \frac{dy}{dt}$

         $= \frac{d( ax + bx^2)}{dt}$

         $= \frac{d(ax)}{dt} + \frac{d(bx^2)}{dt}$

         $= a\frac{dx}{dt} +b\frac{dx^2}{dt}$

         $= a+2bx$

Therefore the differentiated equation is  $y'=a+2bx$

                    Hope it helps you^_^