if y = cos inverse x. Find d^2 y/ dx^2 in terms of y alone
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y=cos(-1x). = cos x
dy/dx = -sinx
d2y/dx2= -cosx
from y=cos(-x)
x=-cos–(y)
then
d2y/dx2=-cos {-cos–(y)}
d2y/dx2 = y
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