If y = cos x log x , then find dy/dx
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Answer:
(dy/dx) = (-sin x)(log x) + (1/x)(cos x)
Explanation:
Given, y = cos x log x
take u = cos x and v = log x
using u*v or multiplication rule
differentiation (u*v) = u' v + v' u
we get, (dy/dx) = (-sin x)(log x) + (1/x)(cos x)
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