Question

if y= e^sin(cosec-1 x) then y'=?
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Answer 1

Answer:

answer in given attached images

Answer 2

Answer: y'=$e^{sin(cosec^{-1}x )} * cos(cosec^{-1}x )*\frac{-1}{x\sqrt{x^{2} -1} }$

Step-by-step explanation:

• Before solving this question we need to know that if we differentiate $e^{x}$ with respect to x the n we get the same result.
• Given, $y=e^{sin(cosec^{-1}x )}$
• So, y'=$e^{sin(cosec^{-1}x )} * cos(cosec^{-1}x )*\frac{-1}{x\sqrt{x^{2} -1} }$
• We have applied chain rule of differentiation here.
• Hence, the required answer is $e^{sin(cosec^{-1}x )} * cos(cosec^{-1}x )*\frac{-1}{x\sqrt{x^{2} -1} }$.

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