if y=e^tanx,then dy/dx is equal to
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hey...
here is your answer dude...
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here is your answer dude...
I hope its help you
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manitkapoor2:
its e^(tan(x))
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let u = tan(x)
[tex]y = e^{tan(x)} = e^{u} \\ \\ \frac{dy}{dx} = \frac{dy}{du} \frac{du}{dx} \\ \\ \frac{du}{dx} = sec^2(x) \\ \\ \frac{dy}{du} = e^{u} = e^{tan(x)} \\ \\ \frac{dy}{dx} = (e^{tan(x)}) (sec^2(x)) = sec^2(x)e^{tan(x)} [/tex]
[tex]y = e^{tan(x)} = e^{u} \\ \\ \frac{dy}{dx} = \frac{dy}{du} \frac{du}{dx} \\ \\ \frac{du}{dx} = sec^2(x) \\ \\ \frac{dy}{du} = e^{u} = e^{tan(x)} \\ \\ \frac{dy}{dx} = (e^{tan(x)}) (sec^2(x)) = sec^2(x)e^{tan(x)} [/tex]
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