Question

If y = e*x /√x find dy/dx where x =1​

Answer 1

x^1/2×e^x-e^x×1/2x^1/2÷(x^1/2)^2(by applying d/dx(u/v) rule)

=2xe^x-e^x÷x

=e^x(2x-1)÷2x^1/2×x

Answer 2

Answer:

$y = \frac{ {e}^{x} }{ \sqrt{x} } \\ on \: differentiating.. \\ \frac{dy}{dx} = \frac{ \sqrt{x} \frac{d( {e}^{x} )}{dx} - {e}^{x} \frac{d( \sqrt{x}) }{dx} }{( { \sqrt{x}) }^{2} } \\ = \frac{ \sqrt{x} {e}^{x} - {e}^{x} \frac{1}{2 \sqrt{x} } }{x} \\ putting \: x = 1 \\ = e - \frac{e}{2} \\ = \frac{e}{2}$