Question

if y+log(x+1)=0,which of the following is true- (a)e^y=xy'-1 (b)y'=-1/x+1 (c)y'+e^y=0 (d)y'=e^y

Answer 1

Step-by-step explanation:

b is the correct answer

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Answer 2

Answer:

(B)The true relation among the given relation is

$y'=-\frac{1}{x+1}$

Step-by-step explanation:

The given equation is $y+log(x+1)=0$ and we are required to find the true relation after differentiating the function.

By differentiation of given relation we get

$\frac{dy}{dx}+\frac{1}{x+1} =0\\= > y'=-\frac{1}{x+1}$

$\because \frac{d}{dx} (log(x+a))=\frac{1}{x+a}$

Therefore,

The true relation among the given relation is

$y'=-\frac{1}{x+1}$

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