Question

p²q – pr² – pq + r², Factorise the expression.​

Answer 1

Answer:

$( {p}^{2} q - p {r}^{2} ) - pq + {r}^{2}$

$p(pq - 1 {r}^{2} ) - (pq - {r}^{2} )$

$(pq - 1 {r}^{2} )(p - 1)$

rewrite

$- {1r}^{2}$

as

$- {r}^{2}$

Ans.

$(pq - {r}^{2} )(p - 1)$

Answer 2

Answer:

$\huge\mathfrak \fcolorbox{blue}{pink}{Answer}$

$\large \mathrm \color{black}{ {p}^{2} q - p {r}^{2} - pq + {r}^{2}}$

$\: \: \: \: \: \: \:$

$\large \mathrm \color{black}{ = > \: \: \: \: {p}^{2}q - pq - p {r}^{2}+ {r}^{2} }$

$\large \mathrm \color{black}{ = > \: \: \: pq(p - 1) - {r}^{2} (p - 1)}$

$\large \mathrm \color{black}{ = > \: \: \: \: \: \: (pq - {r}^{2} )(p - 1)}$