if y = log (√x + √x-a) then dy / dx is
plzz give me a answer it's important plzz
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Step-by-step explanation:
y = log (√x + √x-a)
dy/dx = 1/2 × ( x^-1/2 + 1/2 (x-a )^-1/2 × 1 × 1/(√x + √x-a)
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