Question

if y=p
then find the value of
$\frac{ {y}^{2} }{2} + \frac{y}{4} + \frac{2}{4}$
​

Answer 1

Answer:

$= \frac{p(2p + 2) + 2}{4}$

Step-by-step explanation:

$y = p \\ putting \: value \: of \: y \: in \: given \: eqn \\ \frac{ {y}^{2} }{2} + \frac{y}{4} + \frac{2}{4} \\ = \frac{ {p}^{2} }{2} + \frac{p}{4} + \frac{1}{2} \\ = \frac{2 {p}^{2} + p + 2}{4} \\ = \frac{p(2p + 2) + 2}{4}$

Answer 2

Step-by-step explanation:

hope it is helpful to you