Question

If y = sin^-1 x then find y''.​

Answer 1

Answer:

here u go friend

Step-by-step explanation:

Given that 

y=sin−1x __(1)

then y"=?

from equation (1) to

y=sin−1x

on diff. and we get

dxdy=y′=1−x21

y′=1−x21

again diff and we get

y"=dxd(1−x2)−1/2

y"=−21(1−x)−21−1dxd(1−x2)

=2−1(1−x2)−23(0−2x)

=+22(1−x2)−23<