Question

If y = sin (cotx), then find dy/dx.

Answer 1

dy/dx = -cos(cotx) × cosec^2x
I hope this help u

Answer 2

If y = sin(cotx), then dy/dx is equal to -cos( cotx )cosec²(x).

Given:

y = sin(cotx)

To Find:

dy/dx for y = sin(cotx)

Solution:

→ To calculate the derivative of composite functions we use the chain rule.

If there is a function f(x) = g(h(x)) then the derivative of f(x) that is f'(x) is denoted by:

                            f'(x) = g'( h(x) ) × h'(x)

→ Using the formula for y = sin(cotx):

we get:     $\frac{dy}{dx} = \frac{d(sin(cotx))}{dx} = -cos(cotx)cosec^{2}(x)$

Hence for y = sin(cotx), the dy/dx is equal to -cos( cotx )cosec²(x).

#SPJ2