If y =
then at dy/dx at x=1 is 1/√k. find k
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Given equation can be written as,
y=√x+y
y2=x+y
Differentiating both sides w.r.t. x,
2ydydx=1+dydx
dydx(2y-1)=1
dydx=12y-1, where y2=x+y and y>0y>0.
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