Math, asked by REDBALLZ2321, 11 months ago

If y varies inversely as X^2 and X = 9 when y = 64, how do you find the value of y when x = 4?

Answers

Answered by singhsatyam2611
0

y=k/x^2

64=k/9^2 i.e k= 64×81

y=64×81/4^2=64×81/16=324

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