Question

If y=√x^2+1 – log(1/x+√1+1x^2 ), then find dy/dx​

Answer 1

Answer:

dy/dx = ( x + 1 ) / √(x² + 1 )

Step-by-step explanation:

Given--->

y = √(x² + 1 ) - log { 1 / x + √(1 + x² ) }

To find---> Derivative of given function

Solution--->

1) Plzzz refer the attachment

2) Formula applied

a) log x⁻ⁿ = - n logx

b) d/dx ( √x ) = 1 / 2√x

c) d/dx ( xⁿ ) = n xⁿ⁻¹

Additional information--->

1) d/dx ( xⁿ ) = n xⁿ⁻¹

2) d/dx ( eˣ ) = eˣ

3) d/dx ( aˣ ) = aˣ loga

4) d / dx ( logx ) = 1 / x

5) d/dx ( Sinx ) = Cosx

6) d/dx ( Cosx ) = - Sinx

7) d/dx ( tanx ) = Sec²x

8) d/dx ( Secx) = Secx tanx

9) d/dx ( Cotx ) = - Cosec²x

10) d/dx ( Cosecx ) = - Cosecx Cotx