Question

If y= x^3 – 2x^2, then dy /dx at x = 2 is
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Answer 1

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$y = {x}^{3} - 2 {x}^{2} \\ \\ \frac{dy}{dx} = \frac{d( {x}^{3} - 2 {x}^{2}) }{dx} \\ = 3 {x}^{2} - 4x \\ \\ = 3 {(2)}^{2} - 4(2) = 12 - 8 = 4$