If y = x^3 - 2x^2, then (dy/dx) at x = 2 is
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0
Answer:
=
x
2
−2x+2
x
4
+4
⇒
dx
dy
=
(x
2
−2x+2)
2
(x
2
−2x+2)(4x
3
)−(4x
4
+4)(2x−2)
∴(
dx
dy
)
x=
2
1
=
(
4
1
+1)
2
(
4
1
+1)(4×
8
1
)+(
16
1
+4)
=
25
75
=3
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