if
y = (x^4+x^2+1)/(x^2-x+1)
then ,
dy/dx = ???
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Answered by
4
hii friend...
here is your ans...
________________________
we know the formula of
d( u/v)/dx=(u.dv/dx-v.du/dx)/v^2
so we using this properties in here.......
here , u=x^4+x^2+1 and v=x^2-x+1
now y=(x^4+x^2+1)/(x^2-x+1)
dy/dx = [(x^4+x^2+1)(2x-1)-(x^2-x+1) (4x+2x)](x^2-x+1)
it is your answer
here is your ans...
________________________
we know the formula of
d( u/v)/dx=(u.dv/dx-v.du/dx)/v^2
so we using this properties in here.......
here , u=x^4+x^2+1 and v=x^2-x+1
now y=(x^4+x^2+1)/(x^2-x+1)
dy/dx = [(x^4+x^2+1)(2x-1)-(x^2-x+1) (4x+2x)](x^2-x+1)
it is your answer
Anonymous:
galat hai bahi
Answered by
1
The answer of u r question is..✌️✌️
Is in the pic .✔️
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