If y=x log (x^2-3) , then dy/dx = ?
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Answered by
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Answer:
2x^2/(x^2 -3) + log (x^2 - 3)
Step-by-step explanation:
y = x log (x^2 -3)
Differentiating both sides w.r.t. x
dy/dx = x* d/dx log (x^2 -3) + log (x^2 -3)* d/dx x ( since u*v = u d/dx v + v d/dx u)
dy/dx = x* 1/(x^2 -3)* d/dx (x^2 - 3) + log (x^2 - 3)*1
dy/dx = x/(x^2 - 3) * (2x) + log (x^2 - 3)
dy/dx = 2x^2/(x^2 -3) + log (x^2 - 3)
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0
Concept Introduction:
The area of mathematics concerned with determining the existence and characteristics of function derivatives and integrals using techniques that were first based on the addition of minute differences.
Given,
To find,
Solution:
Final Answer:
The final answer is
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