Question

If y=x/root3-xsqure/60 then find theta and velocity

Answer 1

Answer:

we know:-

Trajectory of projectile motion when u is intial speed inclined Ф angle with horizontal

the equation of projectile is : y = xTanФ - gx²/ 2u²Cos²Ф

and the given equation is : y = √3x - gx²/2

on comparing both the equations ,we get

TanФ = √3

so, Ф = 60°

HENCE, the angle of projectile is 60°

and 2u²Cos²Ф = 2

so u²Cos²Ф = 1

u²cos²60° = 1

u²*(1/2)² = 1

u² = 2²

so, u = 2

Hence, 2 is the initial velocity

Explanation:

Through this process you can solve this.

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