Question

if y=x(x-1)(x-2) then dy/dx is

Answer 1

y = x (x^2 -3x +2 )
y = x^3 -3x^2 +2x
dy/dx = 3x^2 -6x + 2

Answer 2

Solution:-

given by :-

$y = x(x - 1)(x - 2) \\ y = {x}^{3} - 2 {x}^{2} - {x}^{2} + 2x \\ \frac{dy}{dx} = \frac{d}{dx} ( {x}^{3} - 2 {x}^{2} - {x}^{2} + 2x) \\ \frac{dy}{dx} = 3 {x}^{2} - 4x - 2x + 2 \\ \frac{dy}{dx} = 3 {x}^{2} - 6x + 2$