if y=(x2+1)(x3+3) find differentiation of y with respect to x
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Answer:
applying the product rule
dy/dx = (X3 + 3) [d(x2+1)/dx] + [x2+1)(d(x3 + 3)/dx]
dy/dx = (x3 + 3) (2x) + (x2 +1) ( 3x2)
dy/dx = 2x4 +6x + 3x4 + 3x2
dy/dx = 5x4 + 3x2 + 6x
Step-by-step explanation:
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