Question

if y =x2-cosx/sinx find dy/dx

Answer 1

Find dy/dx when y = x^2(cos(x)).

y = x2(cos(x)) therefore we will need to use the product rule,  

dy/dx = u dv/dx + v du/dx

where u = x2 and v = cos(x)

du/dx = 2x and dv/dx = - sin(x), (don't forget the negative symbol when differentiating cosine)

dy/dx = x2(- sin(x)) + cos(x)(2x)

dy/dx = 2x(cos(x)) - x2(sin(x))

Answer 2

Answer:

y = x²(cos(x)) therefore we will need to use the product rule,

dy/dx = u dv/dx + v du/dx

where u = x² and v = cos(x)

du/dx = 2x and dv/dx = - sin(x), (don't forget the negative symbol when differentiating cosine)

dy/dx = x²(- sin(x)) + cos(x)(2x)

dy/dx = 2x(cos(x)) - x²(sin(x))

Step-by-step explanation:

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