Question

if y=x² log x than dy/dx is
a)2xlogx
b)2xlogx+X
c) X
d) none of these​

Answer 1

Step-by-step explanation:

dy/dx = x^2. d/dx(logx) + logx. d/dx(x^2)

dy/dx= x^2. 1/x + logx. 2x

dy/dx= x + 2x. logx

Answer 2

Answer:

answer is B

Step-by-step explanation:

dy/dx = x^2.d(logx)/dx+logx.d(x^2)/dx

= x^2/x + 2x.logx

= 2xlogx + x