Question

If YE×ME=TTT find the numerical value of Y+E+M+T
(hint :TTT=100T+10T+T=T(111)=T(37×3))

Answer 1

Hey mate,

YE × ME = TTT 

(10Y + E)(10M +E) = 100T + 10T + T 

= 111T 

Find two two digit numbers that end in the same thing and make a multiple of 111 

999 is my best guess

It's a multiple of 111 and its also 27×37 

So the answer would be

Y=2 E=7 M=3 T=9

or Y+E+M+T=21 

hope this helps you out!

Answer 2

Answer :

21

Step-by-step explanation :

YE × ME = TTT

Here,

We have to find a number, where the three same numbers came after multiplying, such that the last digits of each number be the same, i.e., the value of E will be same.

Here we go for,

27 × 37 as the value of YE × ME.

The answer we get after multiplying is 999.

Let's see the complete process,

YE × ME = TTT

According to the hint given, the value of TTT must be the multiple of 111, such that when it is multiplied by a number, the digits do not change.

Hence, we go for 27 × 37 = 999

Check the solution,

TTT = T ( 111 )

⇒ 9 ( 111 )

⇒ 999

Hence , the numerical values ;

Y = 2

E = 7

M = 3

T = 9

Adding all the terms,

Y + E + M + T

⇒ 2 + 7 + 3 + 9

⇒ 21

Hence, the answer is 21.