Question

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Answer 1

Answer:

Question

❇️ Refer to the attachment ⬆️❇️

Solution ⬇️

✍️Here;1st term t1(a)=8 and common difference (d)=-5

✍️To find :t2 and t3

<<-------------------------------->>

By using the formula

✍️t2=t1+d=8+(-5)=8-5=3

✍️t3=t2+d=3+(-5)=3-5=-2

✍️ Therefore:8,3,-2 ....is an AP

________________________

Extra formulae

• to find common difference:t2-t1:t3-t2
• to find t=a+(n-1)xd
• to find sum =
• $s(n) = \frac{n}{2} (2a + (n - 1)d)$
• 1st and last term formula:
• $\frac{n}{2} (a +l)$
• To find general form:a,a+d,a+2d,a+3d

Step-by-step explanation:

hope you appreciate this ans

Answer 2

✍️Here;1st term t1(a)=8 and common difference (d)=-5

✍️To find :t2 and t3

<<-------------------------------->>

By using the formula

✍️t2=t1+d=8+(-5)=8-5=3

✍️t3=t2+d=3+(-5)=3-5=-2

✍️ Therefore:8,3,

Extra formulae -

to find common difference:t2-t1:t3-t2

to find t=a+(n-1)xd

to find sum =

s(n) = \frac{n}{2} (2a + (n - 1)d)s(n)=

2

n

(2a+(n−1)d)

1st and last term formula:

\frac{n}{2} (a +l)

2

n

(a+l)

To find general form:a,a+d,a+2d,a+3d

Step-by-step explanation:

hope you appreciate this ans