Math, asked by anushka1374, 30 days ago

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Answered by rk4946545088
2

Answer:

hope this may be helpful

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Answered by Athul4152
1

 \bf\huge\underline{\underline{ Given :- }}

  • quadratic polynomial = (k -1)x² + kx + 1

  • one of its zero is - 3

 \bf\huge\underline{\underline{ To \: Find:- }}

  • Find value of k

 \bf\huge\underline{\underline{ Answer :- }}

as the soultion is - 3 , apply it to the Polynomial.

  • (k-1)x² + kx + 1 = 0 ,

  • \red{\implies} \sf ( k - 1)(-3)² + k(-3) + 1 = 0

  • \red{\implies} \sf ( k - 1)9 -3k + 1 = 0

  • \red{\implies} \sf 9k - 9  -3k + 1 = 0

  • \red{\implies} \sf 6k -8  = 0

  • \red{\implies} \sf 6k   = 8

  • \red{\implies} \sf k   = \frac{8}{6} \\

  • \red{\implies} \sf k   = \frac{4}{3} \\

 \rule{10cm}{0.05cm}

value of k is 4/3

 \rule{10cm}{0.05cm}

The Polynomial :- \red{\implies} \sf   \frac{1}{3}x² + \frac{4}{3}x + 1  \\

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