Question

If you are smart then Solve question 7 ...5th part.

Answer 1

$\alpha + \beta = \frac{ - b}{a} \\ \alpha \beta = \frac{c}{a} \\ \frac{ { \alpha }^{2} }{ \beta } + \frac{ { \beta }^{2} }{ \alpha } \\ taking \: lcm \\ \frac{ { \alpha }^{3} + { \beta }^{3} }{ \alpha \beta } \\ \frac{( \alpha + \beta )( {( \alpha + \beta )}^{2} - 3 \alpha \beta )}{ \alpha \beta } \\ \frac{ \frac{ - b}{a}( \frac{ {b}^{2} - 3ac }{ {a}^{2} } ) }{ \frac{c}{a} }$

Answer 2

hope it will help u now mark me