Question

If you can buy 4 melons for rs.16 then how many can you buy with rs.32

Answer 1

Answer:

The Melons bought in Rs. 32 are 8.

Step-by-step explanation:

Given :

4 melons at = Rs. 16

To find :

Melons at Rs. 32

Solution :

Let Melons bought in Rs. 32 be m

$\begin{tabular}{|c|c|c|}\cline{1-3}\ Melons (x) & 4 & m\\\cline{1-3}\ Cost (y) & Rs.16 & Rs.32 \\\cline{1-3}\end{tabular}$

Direct Variation :

$\bigstar \: {\boxed{\sf{ \frac{x}{y} = k}}}$

$\sf{\implies} \: \dfrac{4}{16} = \dfrac{m}{32} \\ \\ \sf{\implies} \: 4 \times 32 = 16 \times m \\ \\ \sf{\implies} \: 128 = 16m \\ \\ \sf{\implies} \: m = \dfrac{128}{16} \\ \\ \sf{\implies} \: m = 8$

m = 8

$\therefore$ The Melons bought in Rs. 32 are 8.

Answer 2

$\huge\mathbb{SOLUTION:-}$

$\sf\underline{\blue{\:\:\:\:\:Given:-\:\:\:\:\:}}$

Cost of 4 melons=16Rs

$\sf\underline{\purple{\:\:\:\:\:To\:Find:-\:\:\:\:\:}}$

How many melons we can buy in Rs 32

Now

• This is direct variation

let the melons be z

$\begin{tabular}{|c|c|c|}\cline{1-3} \. Melons(x)& 4 & z \\ \cline{1-3} \ cost(y)& Rs.16 & Rs.32\\ \cline{1-3}\end{tabular}$

$\sf\underline{\pink{\:\:\:\:\: Solution:-\:\:\:\:\:}}$

$\sf\implies \dfrac{4}{16}=\dfrac{z}{32}\\ \\ \sf\implies 4\times 32=16\times z\\ \\ \sf\implies 128=16z\\ \\ \sf\implies \cancel{\dfrac{128}{16}}=z\\ \\ \sf\implies 8=z$

$\boxed{\sf{\therefore the\:melons\: bought\:in\:Rs.32= 8}}$