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shift upward by nearly 2 fringes ✌✌✌
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When a thin film is placed in the path of one of the beams, then the optical path of that beam gets longer.
The path difference is
Δx=(μ−1)t
where μ is refractive index, t is thickness.
Given μ=1.5,t=2×10−6 m
∴Δx=(1.5−1)×2×10−6=10−6 m=1 μm
Also path difference Δx=dyD
⇒y=DdΔx
Also fringe width is given by
β=Dλd
=Dd×500×10−9=Dd×0.5 μm
y=Dd×1 μm
=2×Dd×12μm=2β
Hence, central maxima shifts upward by nearly two fringes.
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