Question

IF YOU DON'T KNOW, STAY AWAY!
PLEASE GIVE ME TWO VALUE AND TWO EXAMPLE.

PLEASE ANSWER THE QUESTIONS IN THE PICTURE (THIS IS NOT AN EXAM QUESTION)

UNNECESSARY ANSWERS WILL BE DELETED AND ANSWERS ACCORDING TO QUESTION WILL BE MARK AS BRAINLIEST.

Answer 1

1) b)

∠TQS=90

0

(angle in a semicircle)

∠STQ=∠SQR (angle in the alternate segment)

In Δ TQR,

∠QRS=x=180−(∠STQ+∠TQR)

=180−[40+(90+40)]

=180−170=10

0

c) ANSWER

∠ADC=

2

1

∠AOC

(Angle subtended by a chord on mayor area is half of that subtended on center)

∴∠ADC=

2

1

×130=65

∘

Now, ADCB is cyclic quadrilateral ⇒

Sum of opposite Angles is 180

∘

∴∠ABC+∠ADC=180

∘

∠ABC+65=180

∘

∠ABC=115

∘

Hope it helps you my friend.....

Answer 2

1) b)

∠TQS=90

0

(angle in a semicircle)

∠STQ=∠SQR (angle in the alternate segment)

In Δ TQR,

∠QRS=x=180−(∠STQ+∠TQR)

=180−[40+(90+40)]

=180−170=10

0

c) ANSWER

∠ADC=

2

1

∠AOC

(Angle subtended by a chord on mayor area is half of that subtended on center)

∴∠ADC=

2

1

×130=65

∘

Now, ADCB is cyclic quadrilateral ⇒

Sum of opposite Angles is 180

∘

∴∠ABC+∠ADC=180

∘

∠ABC+65=180

∘

∠ABC=115

∘

Hope it helps you my friend.....