Question

If you flip a coin 10 times, what is the probability of getting heads at least once?

Answer 1

$\huge\underline\mathfrak\red{AnSweR}$

$\textbf{Explanation:}$

$p(at \: least \: once) = 1 - p \: (no \: heads) \\ \\ = \: 1 \: - (\frac{1}{2} ) ^{2} \: \: = \frac{1023}{1024}$

Answer 2

Explanation:

$\begin{lgathered}p(at \: least \: once) = 1 - p \: (no \: heads) \\ \\ = \: 1 \: - (\frac{1}{2} ) ^{2} \: \: = \frac{1023}{1024}\end{lgathered}$

=1−(

2

1

)

2

=

1024

1023