Question

if you give correct answer i will mark as brainlist ​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

<DAB=<BCD. (parallelogram opposite angles are equal)

<DAB+<BAD=180°-(1) (DABP is a cyclic quadilateral)

<BPD+<CPD=180°-(2) (linear pair)

by (1) and(2);

<DAB+<BPD=<BPD+<CPD

<DAB=<CPD

<BCD=<CPD. (<DAB=<BCD)

In triangle PDC;

<BCD=<CPD

therefore triangle PDC is isosceles TRIANGLE

therefore DC=DP

please mark this as brainlist