Question

If you have a solution of [glucose] = 1.0M (12 ml), Tris base = 500 mM (13 ml) and EDTA

= 100 mM (0.6 ml), PREPARE 250 ml of glucose-Tris-EDTA solution containing 2.89

mM glucose, 1.79 mM Tris and 8 mM EDTA. Provide detailed calculations and

explanations for the calculated values that you obtain​

Answer 1

Explanation:

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