Question

If you have given me a loan of Rs. 10,000 for 4 years at a rate of 6% per annum. Find the interest amount and final amount I have to give you.​

Answer 1

S O L U T I O N :

$\underline{\bf{Given\::}}$

• Principal, (P) = Rs.10000
• Rate, (R) = 6%
• Time, (T) = 4 years

$\underline{\bf{Explanation\::}}$

As we know that formula of the Simple Interest;

$\boxed{\bf{S,I. = \frac{PRT}{100} }}$

A/q

$\longrightarrow\tt{S.I = \dfrac{P \times R \times T}{100} }$

$\longrightarrow\tt{S.I = \dfrac{10000 \times 6 \times 4}{100} }$

$\longrightarrow\tt{S.I = \dfrac{100\cancel{00} \times 6 \times 4}{\cancel{100}} }$

$\longrightarrow\tt{S.I = Rs.(100 \times 6 \times 4)}$

$\longrightarrow\bf{S.I = Rs.2400}$

Now,

→ Principal = Amount - S.I

→ Amount = Principal + S.I

→ Amount = 10000 + 2400

→ Amount = Rs.12400

Thus,

The amount & Interest will be Rs.12400 & Rs.2400 .

Answer 2

Answer:

✯ Given :-

• A loan of Rs 10000 for 4 years at a rate of 6 % per annum.

✯ To Find :-

• What is the interest amount and final amount.

✯ Formula Used :-

❶ To find Simple Interest we know that,

$\boxed{\bold{\small{Simple\: Interest\: =\: \dfrac{PRT}{100}}}}$

❷ To find Amount we know that,

$\boxed{\bold{\small{Amount\: =\: Principal\: +\: Simple\: Interest}}}$

✯ Solution :-

Given :

• Principal (P) = Rs 10000
• Rate of Interest (r%) = 6 %
• Time (t) = 4 years

➣ According to the question by using the formula we get,

⇒ S.I = $\dfrac{10000 × 6 × 4}{100}$

⇒ S.I = $\sf\dfrac{\cancel{240000}}{\cancel{100}}$

➠ S.I = Rs 2400

Again, we have to find the amount,

⇒ A = 10000 + 2400

➥ Amount = Rs 12400

$\therefore$ The interest is Rs 2400 and the amount is Rs 12400 .

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