Question

if you know please answer.
(motion)​

Answer 1

Answer:

Find answers in attachment

Explanation:

I have answered first 4 questions. Hope this will help you.

Answer 2

Answer:

First I will solve the intext questions of the NCERT book written in blue.

Ques - 1:- What is the nature of the distance-time graphs for uniform and non uniform motion of an object?

Ans - 1:- An object with uniform motion will have its distance time graph as a diagonal line. An object with non uniform motion will have an irregular distance time graph with a diagonal zig-zag line.

Ques - 2:- What can you say about the motion of an object whose distance time graph is a straight line parallel to the time axis?

Ans - 2:- The object is at rest.

Ques - 3:- What can you say about the motion of an object if its speed time graph is is a straight line parallel to the time axis?

Ans- The object is traveling with a uniform speed.

Ques - 4:- What is the quantity which is measured by the area occupied below the velocity time graph?

Ans- Distance (s)

Ques - 5:- A train is traveling at a speed of 90 kmh⁻¹. Brakes are applied so as to produce a uniform acceleration of -0.5 ms⁻². find how far the train will go before it is brought to rest.

Ans-  u = 90 kmh⁻¹ = 25 ms⁻¹ [Multiply by 5/18]

v = 0 ms⁻¹ [because the train eventually comes to rest]

a = -0.5 ms⁻²

To Find- Value of ‘s’

We will us the equation $v ^{2} - u^{2} = 2as$

$0^{2} - 25^{2} = 2 * -0.5 * s \\-625 = -10s \\\frac{-625}{-10} = s \\62.5 m = s$

The train will travel a distance of 62.5 m before coming to rest.

Ques - 6:- A trolley, while going down an inclined plane has an acceleratoon of 2 cm s⁻². What will be its velocity 3 s after starting?

Ans- u = 0 cm s⁻¹

a = 2 cm s⁻²

t = 3 seconds

v = u + at

v = at [u = 0]

v = 2×3

v = 6 cm s⁻¹

Ques - 7:- A racing car has a uniform acceleration of 4 ms⁻². What distance will it cover in 10 s after the start?

Ans- Since the car starts from rest, its initial velocity will be 0.

u = 0 ms⁻¹

a = 4 ms⁻²

t = 10 s

$s = ut + \frac{1}{2} * a * t^{2} \\s = \frac{1}{2} * a * t^{2} [u = 0] \\s = \frac{1}{2} * 4 * 10^{2} \\s = 2 * 100 \\s = 200$

The racing car covers a distance of 200 m 10 seconds after the start.

Ques - 8:- Derive the three equations of motion graphically.

Ans- Kindly find your answer in the three attachments below.

Hope it helps

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