Question

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⭐This is ICSE class 10 physics question⭐

⭐Correct and fairly answer will be mark as BRAINLIST ⭐


7. A half metre ruler is suspended by a thread from the mid-point of the ruler as shown in Fig. 1.28.
It balances horizontally when a 40 gm and an unknown weight (W) are suspended respectively
from 10cm and the 45cm mark. Calculate the magnitude of weight (W).​

Answer 1

Answer:

30g or 29400 Dynes

Explanation:

formulae :

1) moment of force = force × least distance

2) cw moment = acw moment

i,e d1 × F1 = d2 × F2

given :

d1 = 45 - 25 = 20 cm ; F1 = W Dyne

d2 = 25 - 10 = 15 cm ; F2 = 40 × 980 Dyne

now...

20 × W = 15 × 40 × 980

W = 15 × 40 × 980 / 20

W = 29400 Dyne = 0•294 N

M = 29400/980 = 30 g

Answer 2

Explanation:

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