Question

If you placed two polar substances together, how would they interact?

Answer 1

Explanation:

Answer is :

Q. If 102y = 25, then 10-y equals:

. If 102y = 25, then 10-y equals:(a) -1/5, (b) 1/625, (c) 1/50, (d) 1/25, (e) 1/5

. If 102y = 25, then 10-y equals:(a) -1/5, (b) 1/625, (c) 1/50, (d) 1/25, (e) 1/5Solution:

. If 102y = 25, then 10-y equals:(a) -1/5, (b) 1/625, (c) 1/50, (d) 1/25, (e) 1/5Solution:102y = 25

. If 102y = 25, then 10-y equals:(a) -1/5, (b) 1/625, (c) 1/50, (d) 1/25, (e) 1/5Solution:102y = 25(10y)2 = 52

. If 102y = 25, then 10-y equals:(a) -1/5, (b) 1/625, (c) 1/50, (d) 1/25, (e) 1/5Solution:102y = 25(10y)2 = 5210y = 5

. If 102y = 25, then 10-y equals:(a) -1/5, (b) 1/625, (c) 1/50, (d) 1/25, (e) 1/5Solution:102y = 25(10y)2 = 5210y = 51/10y = 1/5

. If 102y = 25, then 10-y equals:(a) -1/5, (b) 1/625, (c) 1/50, (d) 1/25, (e) 1/5Solution:102y = 25(10y)2 = 5210y = 51/10y = 1/510-y = 1/5

Answer: (e)

Answer 2

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