Physics, asked by akakakaka, 9 months ago

If you release an object from the top of a building whose height is 150 m. Find the time that the object remains in the air just before it touches the floor.

Answers

Answered by 2HARSHIL
0

Answer:

IT'S 35.2 MILLISECONDS....

BRO.. OR

IT WOULD BE THE TIME YOU BLINK YOUR EYE FOR 1 - 2 TIMES ...IT DEPENDS ON YOUR AGE....BRO...MARK ME BRAINLIEST...

Answered by saounksh
5

Answer:

5.53 sec

Explanation:

Given

Height of building, s = 150 m

Initial Velocity of object, u = 0

Acceleration of object, a = g = 9.8 m/s²

Calculation

Equation of motion required

s \:  = ut \:  +  \frac{1}{2} a {t}^{2}

Using the given values, we get

150 = 0*t + (1/2)*(9.8)t²

⇒ 150 = 4.9t²

⇒ t² = 150/4.9 = 1500/49

⇒ t = 10√15/7

t = 5.53 sec (approx)

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