Question

If you require 1.0 × 1023 molecules of nitrogen for the reaction n2 + 3h2 → 2nh3. (i) what is the mass (in grams) of n2 required?

Answer 1

The required of n2 = 1023.

Answer 2

Explanation:

In 1Mol of N2 gas =14*2 = 28g of N2 and no of molecules are 6.022*10^23

Therefore _____g of N2 required for 1.0*10*23 molecules

by cross multiplying the things we get

28 × 6.022 ×10^23 / 1.0× 10^23

= 4.6g of N2