Question

if you roll 1 to 6 numbered dice once, how likely is that the number you randomly get is less than 3? ​

Answer 1

Say p = probability of getting a 6 on each throw = 1/6.

p' = probability of NOT getting a 6 on each throw is 1-p = 5/6.

When you want to compute the probability of multiple (independent) events happening, you must multiply their individual probabilities (not add them). So

The probability of not getting a 6 n times = p' to the nth power.

in this case (5/6) ^6 = 15,625 / 46,656 ~ 0.334