If you roll apir of ice what is the probability that one of them is a 4
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total no. of outcomes n(s)=36
possibility of getting a 4 n(A)=12 {(4,1) (4,2) (4,3)(4,4)(4,5)(4,6)(1,4)(2,4)(3,4)(5,4)(6,4)}
probability of getting a 4 p(A)= n(A)/n(s)
=12/36=3
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